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Ready:
Ok, three guys are invited to their friends bar, when they get there the bouncer at the front gate says, "Pay $10.00 to get in"
So they each pay $10.00 which = $30.00
Then the owner says to the bouncer," I know them, so pay then back with these 5 one dollar bills. The bouncer says, "How am I supposed split these 5 one dollar bills between the three of them, guess I'll keep 2."
He pays the guys back, so now they only paid $9.00 each to get in.
9x3= $27.00 plus the 2 that the bouncer took wich = $29.00
What happend to the other dollar?
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There was $35 originally, actually. The three of them each had ten, which adds up to thirty, and then the owner had five, which adds up to thirty-five. The owner gave the five dollars to the bouncer, and then the three gave him a total of thirty dollars, thus he has all $35. He then gives the three a one dollar bill each, so they have a total of three and he has 35 - 3 = 32, and 32 + 3 = 35; the original amount.
Owner's net money: $-5
Person A's net money: $-9
Person B's net money: $-9
Person C's net money: $-9
Bouncer's net money: $+32
-5 + -9 + -9 + -9 + +32 = 0
So, either you did it wrong or that was a trick question.
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A trick question, I would assume. I mean this dude went crazy trying to figure it out.
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Quote:Originally posted by Paragus
A trick question, I would assume. I mean this dude went crazy trying to figure it out.
You didn't even know the answer? =( And I hope you did not say I went crazy o.O
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Nope, I didnt know the answer. But you must be wrong if this one guy couldnt figure it out and he then went crazy trying to or he was just some tard.
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I believe he made a mistake in his wording. The initial total cost for all three of them to get in was $30.00. When the manager recognized them, he discounted the total cost to $25.00. So, each guy paid $9.00, totalling $27.00. If they had gotten the two bucks from the bouncer, they would have paid the $25.00.
The trick is that, when the manager gives back the 5 bucks, you're now totally 25 dollars, not 30. So there really is no dollar missing at all.
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That would make sense, Burori.
Quote:Originally posted by Paragus
Nope, I didnt know the answer. But you must be wrong if this one guy couldnt figure it out and he then went crazy trying to or he was just some tard.
Is this on a website or something?
@MB: I put the 'bed' in 'BEDMAS.'
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He said to pay them back with the 5 one dollar bills, then he kept 2 becasue it wouldnt be even. So when he gave the guys the 1 dollar each the only paid 9. Which would = 27 plus the 2 from thr bouncer wich then = 29. So this "1" dollar couldnt just walk somewere.
HF - My freind told me.
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Paragus, look at my reply.
You aren't trying to get 30 dollars. You're trying to get 25. They paid a total of 27, and if the bouncer had given them the 2 dollars he kept, they would have paid the 25 dollars the manager intended.
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He only gave the bouncer 5 dollars to pay them back with, tho. Instead of 30.
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Ok, I'll try one more time.
The original total cost was 30 dollars.
The manager gave back 5 dollars.
The new total cost was intended to be 25 dollars. He gave back 5 dollars, so 30-5 = 25. He wanted his friends to pay a total of 25 dollars
The bouncer kept 2 dollars, so that's 2 dollars that the friends didn't get.
So instead of subtracting 5 from their total cost, we can only subtract 3 from their total cost, making it 27 dollars.
Had the bouncer not kept the 2 dollars, they would have only paid 25 dollars.
There is no missing dollar.
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Quote:Originally posted by Hercule
You call that a riddle? That was just bad math!
Math riddles are annoying
"Is it possible for one infinite number to be greater than another infinite number? Prove your answer"
"Measure 2 gallons exactly using a 5 gallon jar and a 3 gallon jar"
*"A woman has 7 children, but only half are boys. How is that possible?"
"Find the next number in the following numerical sequence"
1
11
21
1211
111221
312211
Yes it is possible, with simple mathematics.
1.33333333333~ infinitely will be .1111111111~ infinitely larger than 1.22222222~ infinitely.
All her children are boys.
To measure out 2 gallons exactly, fill the 5 gallon jug twice with the 3 gallon jug, using the left over water in the 3 gallon jug after filling up the 5 gallon jug will equal 1 gallon so doing it twice will give you 2 gallons.
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jello!
Fuck you, Photobucket.
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Try this:
A man is stuck in a box. There are no doors, no windows, no openings of any kind. Inside with him is a round table and a mirror. How does he get out?
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Quote:Originally posted by Goku
Quote:Originally posted by Hercule
You call that a riddle? That was just bad math!
Math riddles are annoying
"Is it possible for one infinite number to be greater than another infinite number? Prove your answer"
"Measure 2 gallons exactly using a 5 gallon jar and a 3 gallon jar"
*"A woman has 7 children, but only half are boys. How is that possible?"
"Find the next number in the following numerical sequence"
1
11
21
1211
111221
312211
Yes it is possible, with simple mathematics.
1.33333333333~ infinitely will be .1111111111~ infinitely larger than 1.22222222~ infinitely.
All her children are boys.
To measure out 2 gallons exactly, fill the 5 gallon jug twice with the 3 gallon jug, using the left over water in the 3 gallon jug after filling up the 5 gallon jug will equal 1 gallon so doing it twice will give you 2 gallons.
But then you have to dispose of the first gallon of water, and thus when you do it again you only have one gallon. You fill the five gallon jar up and then pour as much water from there into te three gallon jar, and thus there are two gallons left in the five gallon jar, since, as we all know, 5 - 3 = 2.
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Here is a differnt version of the missing dollar:
Three men go to a cheap motel, and the desk clerk charges them a sum of $30.00 for the night. The three of them split the cost ten dollars each. Later the manager comes over and tells the desk clerk that he overcharged the men, since the actual cost should have been $25.00. The manager gives the bellboy $5.00 and tells him to give it to the men. The bellboy, however, decides to cheat the men and pockets $2.00, giving each of the men only one dollar.
Now each man has paid $9.00 to stay for the night, and 3 x $9.00 = $27.00. The bellboy has pocketed $2.00. But $27.00 + $2.00 = $29.00. Where is the missing $1.00? WTF?
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Quote:Originally posted by Paragus
Here is a differnt version of the missing dollar:
Three men go to a cheap motel, and the desk clerk charges them a sum of $30.00 for the night. The three of them split the cost ten dollars each. Later the manager comes over and tells the desk clerk that he overcharged the men, since the actual cost should have been $25.00. The manager gives the bellboy $5.00 and tells him to give it to the men. The bellboy, however, decides to cheat the men and pockets $2.00, giving each of the men only one dollar.
Now each man has paid $9.00 to stay for the night, and 3 x $9.00 = $27.00. The bellboy has pocketed $2.00. But $27.00 + $2.00 = $29.00. Where is the missing $1.00? WTF?
My original post still answers this. o.o'
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Quote:Originally posted by Goku
Quote:Originally posted by Hercule
You call that a riddle? That was just bad math!
Math riddles are annoying
*"A woman has 7 children, but only half are boys. How is that possible?"
All her children are boys.
It may be a wording error, but the riddle was only half are boys. So your answer cannot possibly be correct.
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Three boys and a hermaphodite. It may not the the answer, but it. . .kinda works. =P
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Quote:Originally posted by HellFighter 17
Three boys and a Bra. It may not the the answer, but it. . .kinda works. =P
I corrected your wording on that =x
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