Riddle of Sphinx's Cousin

[Retane]

Buterfly or moth =\

[Violet]

That is what I was thinking, and then, i think it soulds like a catipillar going into a moth, or whatever those bugs are that turn into moths.>.>


EDIT: Removed? isn't that like, married out or something? Could be disowned, idk.

[Jewtastic]

Cousin once removed=Your dad's cousin's son.

I believe. Might be wrong but there ya go.

Edit: In that context I think I know. There is an old story where the sphinx asks a riddle to anyone who passes.

In the morning I walk on all fours
In the afternoon I walk on two legs
and in the evening I walk on three.


What am I?

[Uno]

Well...I've desided to post a riddle myself, cus I've been dying to post it. I'll give you all til 7 pm, EST to answer my riddle. Uh...you'll get only 100z, I'm not very generous...

A man needs to deliver a parcel from Point A to Point B. He can carry up to four days of food, but the travel time is seven days. He is able to bring companions with him along the trip, all which can only carry four days of food. All companions must be retured to Point A alive. The man can stay at Point B, he doesn't need to return to Point A. Now...the riddle...

What is the least amount of companions the man can take to get from Point A to Point B?

Edit: Oh...explain your resoning and whatever...

[Burter Jr]

Originally posted by Murasaki
In the morning I walk on all fours
In the afternoon I walk on two legs
and in the evening I walk on three.

Yea, I've read that story. I forgot what it was. I read it in school.

It's a human.

Morning = baby = crawl

Afternoon = adult = walk

Evening = elder = walk on cane

[Retane]

Originally posted by Koola
Well...I've desided to post a riddle myself, cus I've been dying to post it. I'll give you all til 7 pm, EST to answer my riddle. Uh...you'll get only 100z, I'm not very generous...

A man needs to deliver a parcel from Point A to Point B. He can carry up to four days of food, but the travel time is seven days. He is able to bring companions with him along the trip, all which can only carry four days of food. All companions must be retured to Point A alive. The man can stay at Point B, he doesn't need to return to Point A. Now...the riddle...

What is the least amount of companions the man can take to get from Point A to Point B?

Edit: Oh...explain your resoning and whatever...

He would need three companions

Ok, considering you mean he must eat and such each day. His food could last him the final four days.

Day1
Everyone eats.so:
M-3
C1-3
C2-3
C3-3

C3 givesC1, C2 and M 1 food.food each so:
M-4
C1-4
C2-4
C3-0




Day 2
C3 returns home.
M-4
C1-4
C2-4

They eat.
M-3
C1-3
C2-3

C2 needs only 1 food to return home So he gives his food to M and C1 so:
M-4
C1-4
C2-1



Day3
C2 returns home.

The last two eat.
M-3
C1-3

C1 only neds 2 to get home. so he gives 1 to M so:
M-4
C1-2


Day4-7
M has enough to make it. C1 returns home.

[Retane]

I dont get the 'eye's' part of the riddle>_>

[The Not Cool Not Tapion]

The all seeing eye in the pyramid or whatever. It's symbology.

[Uno]

So far, no one has goten my riddle. Two more hours!

[Uno]

He didn't, that's wrong.

[Alsa]

Originally posted by Murasaki
Cousin once removed=Your dad's cousin's son.

I believe. Might be wrong but there ya go.

Edit: In that context I think I know. There is an old story where the sphinx asks a riddle to anyone who passes.

In the morning I walk on all fours
In the afternoon I walk on two legs
and in the evening I walk on three.


What am I?

THATS THE OLDEST RIDDLE! A MAN! IT DATES BACK TO THE EGYPTIANS!

[Hellfighter 17]

Originally posted by Bujin
Yep the all seeing eye is the pyramid.

The three faces: George- Human. Eagle- Beast. Pyramid- Stone.

4 eyes: 2 for George. 1 for each the pyramid and the eagle.

Etc.

It just kinda came to me and I reached into my wallet and sure enough.

Then that joke is discriminatory. >=o

[Retane]

Originally posted by Koola
He didn't, that's wrong.

Well... technically there isn't enough detail to fully understand the riddle.

But while I go complie a few questions... so I can understnad what you are asking, I'll say...

OK.. looking at the riddle, it's possibly a trick question.

What is the least amount of companions the man can take to get from Point A to Point B?

None. He can't take them to Point B?





If thats not the answer, then tell me this If Companion 1 moves 1 space to day 1... he eats a food right? And does he have to have a food to return to Point A? Or can he get there without any food and his hunger be satisfied by his homeland? Also This appies to the Man. Can he eat his last bit of food on day 6 and get fed when he reaches his destination at day 7?

Also! Is this food perishable?

Next, From Point A the man would reach point b in 7 days, not on the eith day correct?

If you cant have these answered within 10 minutes of this edit.. then well I'm blaming you for messing up my chance of reaching the deadline.

[Uno]

Originally posted by Koola
Well...I've desided to post a riddle myself, cus I've been dying to post it. I'll give you all til 7 pm, EST to answer my riddle. Uh...you'll get only 100z, I'm not very generous...

A man needs to deliver a parcel from Point A to Point B. He can carry up to four days of food, but the travel time is seven days. He is able to bring companions with him along the trip, all which can only carry four days of food. All companions must be retured to Point A alive. The man can stay at Point B, he doesn't need to return to Point A. Now...the riddle...

What is the least amount of companions the man can take to get from Point A to Point B?

Edit: Oh...explain your resoning and whatever...

Lets go like this...

PA---D1---D2---D3---D4---D5---D6---D7---PB

Now, the man needs to get from PA to PB, right? It takes seven days, like my chart above shows. A companion can turn back and go home. To move a space takes a food. The food isn't perishible ethier.

Edit: Oh! I'm extending it to 8:00 EST.

[Hellfighter 17]

Then Retane is right since day seven should equate to point B.

[Uno]

No, here's how it works, while they are traveling, they must stop for the night and eat. So, they must eat 7 times, but the man must travel 8 days, and 7 nights. nights=1 food.

[Hellfighter 17]

That completely changes the riddle, then. =\

[Uno]

Actually, it doesn't. They still must travel the same amount that I said in the beginning, but I understand if I made it hard to understand...I'm like that sometimes. Forget this riddle for now, I'll post one up latter so it won't be confusing, cus now my brain hurts.

[Retane]

Ok. Fuck it. Here! Lets see if I got the outlines right now then. I'll walk the process bacckwards this time since I have the rules understood. Food only gets ate on a D#. Not a P#

The object of the riddle is to get the deliverer alone by D4. When he is at D3 Companion 1 would have to give him a food after they eat so that once the deliverer reaches D4 and eats he will have 3 food left.


THe following is what the graph would look like after Deleivere4re ate at night


PA---D1---D2---D3---D4---D5---D6---D7---PB

3 2 1 0 The end


Now, going from that part. THat would mean that Companion 1 would have to have 3 foods on D3 after they had aten so he could give one to the Deleiver. His path would then look like this:

PA---D1---D2---D3---D4---D5---D6---D7---PB

0 1 2

Now!

How do we get Companion 1 and the Deleiverer to D3 with each one having 3 food?

Well Companion 2 Would only need 1 food after he eats at D2 to get him home like so.


PA---D1---D2---D3---D4---D5---D6---D7---PB

0 1

So! He will need to supply his freinds with food to have 4 food before they go to D3. Therefore he must have 3 foods after he has eaten on D2 and given htem each 1 leaving him withone left to go back to D1 and eat it them to PA.

So! That means aonther Companion must see that everyone havd 4 foods before they got to D2. Enter Companion 3! Ok. So Companion 3, with the other two companins and deliverer... They start at Pa with 4. They move to D1 and eat and all have 3 food left. Companion 3 gives his other 3 to the other 3 leaving him with zero, but he can return home without needing anymore food. COmpanion 2, COmnpanion 1, and Deliverer would ahve 4 foods then to take to D2.



PA---D1---D2---D3---D4---D5---D6---D7---PB

0









Thats three companions!

Anyone that can use under three using that logic let me know.


-----------------------------



I want to find the idiot that created this riddle and bash their skull in because, personally, I can point out multiple answers.

I can point other ways to do this as well that might only take 2. But this would involve Companion 2 going to PA, then comping back out to meet Companion 1 on say, day2 to give him food so they xcan both return to PA alive.

Or I can point an answer out that wouldn't use any. THis involves Deleiverer taking food to D1 and dropping it off going to PA and getting some more then going back to D1 drop some more off and so on and stockpiling enough to do the same with the next day and so on.

[Uno]

ALLLLLLLLLRIGHT ladys and gentle men! Because of the confusion of the riddle...I'm gonna recreate it. Please explain your answer when you give it. You have until...6:00pm EST to slove it. As well, I'm doubling the zeni! You will now get 200z instead! I put the riddle in "Saw" form, here you go!

---------------------------------------------

You are stuck in a large room, with a big walkway down the middle. It starts at the end of the room, and ends near the only door in the room. There are eight spaces, the one you are on says "START!" and the one near the door says "D7/FINISH!". Baisly, it looks like this...

START!---D1---D2---D3---D4---D5---D6---D7/FINISH!

The freacky clown puppet is hanging from the ceiling and is staring at you at you with his beady eyes. Suddenly, the room shakes and the floor disappears, all but the walkway. The floor is then replaced by lava.

"Welcome (insert name here), today, you're gonna try and fight for your life! As you can see, your on a board game, but you are the piece this time! You have to manuver youself so that reach the finish. But to do that, you need these!" The puppet holds up a large token of some kind.

"Look in the backpack next to your feet, there will be four tokens! To move to a D space, you must lose a token. If you run out, Uh Oh!, the floor will cave-in and you will die! But don't worry (insert name here), you get friends, my friends!" The wall behind you opens up to see hundereds of square boxs with wheels on the bottom, and a clown head on the top. Each of them holds four tokens.

"Using what little wit you have and my friend's help, you can fight your way to safety. Here are the rules!

1. If you or my friends are out of tokens on the board, unless you are on the START or FINISH space, you will die.

2. You can't leave a token on a square, or you'll die.

3. If someone moves, you all have to move. If not, you'll die.

4. My friends must be returned to START, or you'll die.

5. You may exchange tokens.

6. You must finish in 7 turns.

7. Try to use the least amount of my friends. The lesser , the better!

8. You have exactly 18 hours to think until the timer goes off and the room explodes. Have fun!!!